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x^2+5x+60=220
We move all terms to the left:
x^2+5x+60-(220)=0
We add all the numbers together, and all the variables
x^2+5x-160=0
a = 1; b = 5; c = -160;
Δ = b2-4ac
Δ = 52-4·1·(-160)
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{665}}{2*1}=\frac{-5-\sqrt{665}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{665}}{2*1}=\frac{-5+\sqrt{665}}{2} $
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